Math, asked by iamnandhanarajesh23, 3 months ago

D and E are points on the sides PR and QR respectively of a triangle PQR right angled at R. Prove that PE2+ QD2= PQ2 + DE2.

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Answered by tejas9193

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and E are points on the sides PR and QR respectively of a triangle PQR right angled at R. Prove that PE2+ QD2= PQ2 + DE2.

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