D and E are position on sides AB and AC respectively of triangle ABC such that ar(triangle DBC) = ar (triangle EBC ) prove that (DE !!BC)
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area (DBC) = area (EBC)
We know that Area of Any triangle is
1/2*b*h
Since, Area of ΔDBC and ΔEBC are same and Base is common for both the triangles
⇒ height of ΔDBC is also equal to the height of ΔBEC
⇒ h1 = h2
Hence BC || DE
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We know that Area of Any triangle is
1/2*b*h
Since, Area of ΔDBC and ΔEBC are same and Base is common for both the triangles
⇒ height of ΔDBC is also equal to the height of ΔBEC
⇒ h1 = h2
Hence BC || DE
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