D and E are two points on side of triangle ABC, such that BD=DE=EC. Prove that ar(ABD)=ar(ADE)=ar(AEC).
Hint: Draw AL perpendicular to BC
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We know that,
Area of a triangle × Base × Altitude

It is given that DE = BD = EC
⇒ 
⇒ Area (ΔADE) = Area (ΔABD) = Area (ΔAEC)
It can be observed that Budhia has divided her field into 3 equal parts.
Area of a triangle × Base × Altitude

It is given that DE = BD = EC
⇒ 
⇒ Area (ΔADE) = Area (ΔABD) = Area (ΔAEC)
It can be observed that Budhia has divided her field into 3 equal parts.
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