English, asked by benbob, 4 months ago


D) At high pressure van der Waals' constant 'b'domainates over 'a'
ents:​

Answers

Answered by Nylucy
1

Answer:

Option A is correct. Boyle temperature is the temperature at which a non-ideal gas behaves like an ideal gas over an appreciable range of pressure.

Option B is correct.

Option C is wrong. At low pressure ‘V’ is large and ‘b’ is negligible in comparison with V. The Vander Waals equation reduces to:

(P +

V

2

a

) V = RT

PV + a/ V = RT

PV = RT –

V

a

or PV < RT Hence, van der Waals' constant 'a' dominates over 'b'.

Option D is correct.

V

2

a

may be neglected in comparison with P. The Vander Waals equation becomes:

P (V – b) = RT

PV – Pb = RT

PV = RT + Pb or PV > RT

Hence, van der Waals' constant 'b' dominates over 'a'.

Hence, A, B, D are the answers.

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