Question

d) Calculate the de-Broglie wavelength of
the electrons acclerated through
potential difference of 56 V..
a​

Answer 1

Answer:

(b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V. Therefore, the momentum of each electron is 4.04 × 10−24 kg m s−1 . ... Therefore, the de Broglie wavelength of each electron is 0.1639 nm.

Explanation:

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