Question

D) Draw the graph of the linear equation 2x + y = 4.
(Plot at least 3 points ).
Rewrite and complete the following table

Answer 1

EXPLANATION.

Graph of the linear equation,

⇒ F(x) = 2x + y = 4.

As we know that,

Put the value of x = 0 in equation, we get.

⇒ 2(0) + y = 4.

⇒ y = 4.

Their Co-ordinates = (0,4).

Put the value of y = 0 in equation, we get.

⇒ 2x + (0) = 4.

⇒ 2x = 4.

x = 2.

Their Co-ordinates = (2,0).

Answer 2

Gɪᴠᴇɴ :

Linear equation,

➢ $\bf\blue{2x\:+\:y\:=\:4}$

❶ Substituting 'x = 0' in the given equation, we get

$:\implies\:\:\sf{2\times{0}\:+\:y\:=\:4}$

$:\implies\:\:\sf{0\:+\:y\:=\:4}$

$:\implies\:\:\bf{y\:=\:4}$

❷ Substituting 'x = 1' in the given equation, we get

$:\implies\:\:\sf{2\times{1}\:+\:y\:=\:4}$

$:\implies\:\:\sf{2\:+\:y\:=\:4}$

$:\implies\:\:\sf{y\:=\:4\:-\:2}$

$:\implies\:\:\bf{y\:=\:2}$

❸ Substituting 'x = 2' in the given equation, we get

$:\implies\:\:\sf{2\times{2}\:+\:y\:=\:4}$

$:\implies\:\:\sf{4\:+\:y\:=\:4}$

$:\implies\:\:\sf{y\:=\:4\:-\:4}$

$:\implies\:\:\bf{y\:=\:0}$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 4 \\ \\ \sf 1 & \sf 2 \\ \\ \sf 2 & \sf 0 \end{array}}$

➢ Now draw a graph using the points (0 , 4), (1 , 2) & (2 , 0)

➢ See the attachment graph.