Math, asked by harshapedakota6, 6 months ago

d/dtheta { sinh [log (cot (pi/4+theta)]

Answers

Answered by psidharth959
0

Answer:

-{sinh(cos(π/4+θ)}/sin^3(π/4)

Step-by-step explanation:

d/dθ(sinh[log(cot(π/4+θ)

sinh(d/dθ(log(cot(π/4+θ))))             {sinh is a constant with respect to θ}

[sinh(-cosec^2(π/4+θ)]/cot(π/4+θ)  

on further solving,

-[sinh(cos(π/4+θ))]/sin^3(π/4+θ)                                                                      

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