Math, asked by sohags406, 9 days ago

d/dx (cos^2x)=??
d/dx (sin^2x)=??​

Answers

Answered by DEBOBROTABHATTACHARY
0

d/dx (cos^2x)

= 2cos(x) . d/dx(cos x)

= 2 cos(x) . (- sin x)

= - 2 cos(x) sin(x) (ans.)

d/dx (sin^2x)

= 2sin(x) . d/dx(sin x)

= 2 sin(x) cos(x) (ans.)

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