Question

d/dx cot x - sec x - log 10 ^x
hurry up guys​

Answer 1

ANSWER :

$\frac{d}{dx} (\cot( \alpha ) - \sec( \alpha ) - log( {10}^{ \alpha } ) ) \\ \\ \\ \frac{d}{dx} \cot( \alpha ) - \frac{d}{dx} \sec( \alpha ) - \frac{d}{dx} log( {10}^{ \alpha } ) \\ \\ \\ = - { \csc}^{2} \alpha - \sec( \alpha ) . \tan( \alpha )$