Question

d/dx (log tanx)
(a) 2 sec 2.1
(b) 2 cosec 2x
(d) cosec 2x
(c) sec 2.x
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Answer 1

Answer:

2 cosec 2x

Step-by-step explanation:

d/dx log{f(x)}= 1/x

but as tanx is not x so

= (1/tanx)* d/dx tanx

= {1/(sinx/cosx)}* sec²x

= (cosx/sinx)*1/cos²x

= 1/sinx.cosx

= 1/(sin2x/2)

= 2cosec2x

hence proved