Math, asked by indusati26121, 4 months ago

D/dx of logx to the base a

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Answered by as1691503
2

Answer:

By the change of base formula for logarithms, we can write logᵪa as ln(a)/ln(x). Now this is just an application of chain rule, with ln(a)/x as the outer function. So the derivative is -ln(a)/((ln(x))²)·(1/x).

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