d/dx {tan^-1(e^x)} is equal is
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QUESTION ⬇️
d/dx {tan^-1(e^x)} is equal is?
ANSWER ⬇️
we can find #f'(x)=frac{e^x}{1+e^{2x}}#.
Note: #[tan^{-1}(x)]'={1}/{1+x^2}#.
By Chain Rule,
#f'(x)={1}/{1+(e^x)^2}cdot e^x={e^x}/{1+e^{2x}}#
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