d/dx (tanx) please solve this....
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Hi__________________
Tanx=sinx/cosx
d/dx(sinx/cosx)
d/dx(sinx)+d/dx(1/cosx)
cosx+d/dx(cosx)^-1
cosx-1/(cosx)^-2 d/dxcosx
cosx+sinx/cos^2x
cosx+tanxsecx
it is the answer
cosx+tanxsecx
because cosx=1/secx
hope it help u
Tanx=sinx/cosx
d/dx(sinx/cosx)
d/dx(sinx)+d/dx(1/cosx)
cosx+d/dx(cosx)^-1
cosx-1/(cosx)^-2 d/dxcosx
cosx+sinx/cos^2x
cosx+tanxsecx
it is the answer
cosx+tanxsecx
because cosx=1/secx
hope it help u
SonuRahulMadduri:
its wrong
sorry
its correct
It got correct or not???
u r right .
Mark me brainliest plz
u r right .
tq
hey its not right answer
answer is sec^2x
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