D,E and F are the midpoints of the sides of triangle ABC. Prove that perimeter of triangle DEF is half of the perimeter of triangle ABC
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Step-by-step explanation:
let sides AB=2a, BC=2b, AC=2c
given D, E, F are midpoints
by midpoint thm DE=1/2*BC =1/2*2b=b
similarly EF=1/2*AB=1/2*2a=a
DF=1/2*AC=1/2*2c=c
from above analysis we see that preimetre of triangle ABC=2(a+b+c) and perimetre of triangle DEF=a+b+c
by this we prove that triangle DEF perimetre is 1/2 of perimetre of triangle ABC
Answered by
0
perimeter of triangle ABC= 2(a+b+c)
perimeter of triangle DEF= a+b+c.
hence triangle DEF = 1/2 perimeter of triangle ABC
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