Question

D , E and F are the points on sides BC , CA and AB respectively of △ABC . Such that AD bisects ∠A , BE bisects ∠B and CF bisects ∠C . If AB = 5cm , BC = 8cm and CA = 4cm , determine AF , CE and BD ...Draw the fig also

Answer 1

it is given that AB=5 BC=8 CA=4
since AD is bisector of A
AB/AC=BD/CD
5÷4=BD/BC-BD
5/4=BD/8-BD
40-5BD=4BD
40=9BD
BD=40/9
BE is bisector of B
AB/BC=AE/EC
5/8=AC-EC/EC
5/8=4-EC/EC
5EC=32-8CE
5CE+8CE=32
13CE=32
CE=32/13
CF is a bisector of C
BC/CA=BF/CF
8/4=AB-AF/AF
8/4=5-AF/AF
8AF=20-4AF
12AF=20
AF=5/3
AF=5/3 CE=32/12 BD=40/9

Answer 2

Answer:

the answer is very simple

Step-by-step explanation:

as you there are 3 mid points on three sides respectively

af =1/2 of ab .....ce=1/2 ac.......bd =1/2 of bc

very simple bro just substitute the values given