If sintheta=2/5. Find the value of cotsquare theta
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Theta is written as @
Sin@=2/5 =hieght/hypotenuse
Let hieght =2x and hypotenuse =5x
By Pythagoras theorem,
Base =√21x²
Cot²@=(base/hieght)²=21x²/4x²=21/4
Sin@=2/5 =hieght/hypotenuse
Let hieght =2x and hypotenuse =5x
By Pythagoras theorem,
Base =√21x²
Cot²@=(base/hieght)²=21x²/4x²=21/4
sidcuberzz:
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It was actually very easy
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