Question

D, E, Fare points on the sides BC, CA, AB respectively, triangle ABC that AD, BE, CF are concurrent at O. Show that OD/AD+OE/BE+OF/CF=1​

Answer 1

Step-by-step explanation:

It is given that AB =5,BC=8, CA=4

since AD is bisector of A

AB/AC=BD/CD

5÷4=BD/BC -BD

5/4=BD/8-BD

40-5 BD =4 BD

40 =9 BD

BD =40/9

BE is bisector of B

AB/BC =AE/EC

5/8=AC-EC/EC

5/8=4-EC/EC

5 CE +8CE=32

13CE =3

CE=32/13

CF is bisector of C

BC/CA =AF/AF

8AF=20-4AF

12AF=20

AF=5/3

AF=5/3 , CE=32/12,BD=40/9

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