Math, asked by poonamdwivedi9302, 6 months ago

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Factorise 4²-4y- 77​

Answers

Answered by Anonymous
3

Answer:

 {y}^{2}  - 4y - 77 = 0 \\  {y}^{2}  - 4y - 77 = 0 \\  {y}^{2}   - 11y + 7y - 77 = 0 \\y(y - 11) + 7(y -11) = 0 \\ (y - 11)(y + 7) = 0 \\ y - 11 = 0 \ \:  \:  \: or \:  \:  \: y + 7 = 0 \\ y = 11 \:  \:  \:  \:  \:  \: or \:  \:  \:  \:  \: y =  - 7

Answered by Brainlyboy00
0

Answer:

Answer:</p><p></p><p>\begin{gathered} {y}^{2} - 4y - 77 = 0 \\ {y}^{2} - 4y - 77 = 0 \\ {y}^{2} - 11y + 7y - 77 = 0 \\y(y - 11) + 7(y -11) = 0 \\ (y - 11)(y + 7) = 0 \\ y - 11 = 0 \ \: \: \: or \: \: \: y + 7 = 0 \\ y = 11 \: \: \: \: \: \: or \: \: \: \: \: y = - 7\end{gathered}y2−4y−77=0y2−4y−77=0y2−11y+7y−77=0y(y−11)+7(y−11)=0(y−11)(y+7)=0y−11=0 ory+7=0y=11ory=−7</p><p></p><p>

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