(D)
family of 3 children, the probability of having at least one boy is.............
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Answer:
let,boy-b and girl -g
so the total outcomes are
gbb , ggg , gbg , ggb , bgg , bbg , bbb , bgb
favourable outcomes = 7
probability of getting atleat 1 boy =7/8
Step-by-step explanation:
Total children = 3
A child can be a boy or a girl
Probability of being a boy =
Probability of being a girl =
Formula :
Probability of success = p = being a boy =
Probability of failure = q = being a girl =
n = 3
r = 0
So, probability of having at least 1 boy = 1 - prob. of having 0 boy = 1- 0.125 = 0.875
Hence probability of having at least 1 boy is 0.875
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