d. Find the sum of 40
40 positive integers divisible
by 6?
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Answered by
1
Answer:
Expert Answer:
We know that the first 40 positive integers divisible by 6 are 6,12,18,....
This is an AP with a = 6 and d = 6.
S40= 20[2(6) +(40-1)6] =20[12+234] =4920.
Step-by-step explanation:
hope you are satisfied with the answer
Answered by
1
Answer:
a=6
d=6
S40=?
≈4920
hope it's help full for u
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