Question

d) In Fig. 8. AB and CD are two straight lines intersecting at O.
1 EO = FB = 3 cm and FO = AE = 2 cm, prove that triangle ACO = triangle BDO.​

Answer 1

Answer:

Step-by-step explanation:

As EO = FB = 3 cm and

     AE = FO = 2 cm

So, EO + AE =3 + 2 = 5 cm = AO

      FB + FO =3 + 2 = 5 cm = BO

Hence, AO = BO, ________(i)

Now, in ΔACO and ΔBDO

AO = BO             (from (i))

∠AOC = ∠BOD   (vertically opp. angles)

OC = OD (given 5cm)

∴ ΔACO ≅ ΔBDO

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