D is a point on base BC of a ΔABC such that 2BD=DC.Prove that : ar(ΔABD)=1/3 ar (ΔABC).
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Step-by-step explanation:
DC/BD=2/1
therefore DC=2 and BD=1
∆ABC / ∆ABD=BC/BD
=BD+DC/BD
=1+2/1
=3/1
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