Math, asked by Anonymous, 11 months ago

D is a point on hypotenuse AC of ∆ ABC, such that BD perpendicular AC, DM perpendicular BC and DN perpendicular AB. Prove that:


(i) \:   {DM}^{2}  = DN × MC \  \textless \ br /\  \textgreater \  \\ (ii )  \:  {DN}^{2} = DM × AN \:  \:  \:

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Answered by Anonymous
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I hope you like it Palak !

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