D is a point on side BC of a triangle ABC such tha angle adc equal angle bac. prove that ca upon CD equal to cb upon ca
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Step-by-step explanation:
Given,
Angle ADC = Angle BAC
Therefore,
AC = CB (sides opposite to equal angles are equal)
But,
angle ADC is the height of triangle ABC.
Therefore,
angle ADC = angle BAC = 90°
Hence, triangle ABC is a right angled triangle
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