Math, asked by adityasingh4212, 11 months ago

D is a point on side BC of a triangle ABC such tha angle adc equal angle bac. prove that ca upon CD equal to cb upon ca​

Answers

Answered by deepakjena63
0

Step-by-step explanation:

Given,

Angle ADC = Angle BAC

Therefore,

AC = CB (sides opposite to equal angles are equal)

But,

angle ADC is the height of triangle ABC.

Therefore,

angle ADC = angle BAC = 90°

Hence, triangle ABC is a right angled triangle

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