Question

D is a point on the side bc of a triangle ABC such that
Angle ADC =Angle BAC
Show that

${ca}^{2} = bc \times cd$
​

Answer 1

Answer

Hey mate

I will help u

In triangle ADC and triangle BAC

Angle ADC = angle BAC.......... (given)

Angle DAC= Angle BCA.......... (common angle)

Therefore

triangle ADC similar triangle BAC........ By (A. A. Criteria)

Ad/ BA= DC/ AC= AC/BC

THEREFORE

DC/ AC= AC/BC

Hence,

Ac2= DC* BC

Hence proved

Answer 2

Answer:

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