Using Coordinate geometry prove Pythagoras theorem.
Answers
Answer:
given ABC is a right angle triangle at b is equal to 90 degree
to prove AC square is equal to a b square + BC square
constructions draw BM perpendicular to to AC
proof:-in triangle abc and triangle BMC
angle b is equal to angle m is equal to 90 degree
angle C is equal to angle C is equal to common
therefore triangle ABC is similar to triangle BMC by a similarity criteria
now we can say that...
....
now in triangle abc and triangle AMC.
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Answer:
Clearly the question is vague or rather incomplete...In terms of solving- Data Insufficient.
Why?
LET'S SEE....
Most of the answers to this question I have come across is done through plane geometry proofs of similarity etc. while the question strictly says use coordinate geometry...
Now talking of Rectangular Cartesian Coordinate System, the proof to the theorem is done using the distance formula....The folly and blunder committed in this process is that distance formula itself was derived from Pythagoras theorem and we use the distance formula to prove it back...
This is surely absurd....
THEREFORE TO DRAW A CONCLUSION,
PYTHAGORAS THEOREM CANNOT BE PROVED USING RECTANGULAR CARTESIAN COORDINATE GEOMETRY