Question

D is any point on side AC of a ∆ABC with AB=AC.Show that CD<BD

Answer 1

◆Ekansh Nimbalkar◆
hello friend here is your required answer

Answer 2

Given - AB = AC

To prove -- BD > CD

Proof -- Since AB = AC
∠ABC = ∠ACB  (By Isosceles Triangle property) ----(i)

Here clearly,
∠ABC > ∠CBD
∠ACB > ∠CBD ---from (i)
∠DCB > ∠CBD
BD > CD   (Angle opposite to greater side is greater in a triangle)

Hence Proved!

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