Math, asked by tanujreddy86, 4 months ago

D) Σ Η
LULU
44.
n, na
Consider N = identical cells, each of emf ε and internal resistance r. Suppos
ni
The combination drives a current in an external resister. The current in the extern
resistance is
n 2
n, E
na
B)
A)
D)
C)
ne
R+
nr
n,
R+
nr
N₂
R+
R+hr
R+hr
n₂
n
п,
such lines are connected in parallel.the combination drives a current in an external resister.The current in the resistence​

Answers

Answered by Anonymous
1

Answer:

a) Total emf =n

1

E

in 1 row

Total emf in all news =n

1

E

Total resistance in one row =n

1

r

Total resistance in all rows =

n

2

n

1

r

Net resistance =

n

2

n

1

r

+R

Current =

n

1

r/n

2

+R

n

1

E

=

n

1

r+n

2

R

n

1

n

2

E

b) i=

n

1

r+n

2

R

n

1

n

2

E

for i=max

n

1

r+n

2

R=min

⇒(

n

1

r

n

2

R

)

2

+2

n

1

m

2

R

=min

it is min, when

n

1

r

=

n

2

R

→n

1

r=n

2

R

i is max when n

1

r=n

2

R

Answered by Anonymous
0

a) Total emf =n

1

E

in 1 row

Total emf in all news =n

1

E

Total resistance in one row =n

1

r

Total resistance in all rows =

n

2

n

1

r

Net resistance =

n

2

n

1

r

+R

Current =

n

1

r/n

2

+R

n

1

E

=

n

1

r+n

2

R

n

1

n

2

E

b) i=

n

1

r+n

2

R

n

1

n

2

E

for i=max

n

1

r+n

2

R=min

⇒(

n

1

r

n

2

R

)

2

+2

n

1

m

2

R

=min

it is min, when

n

1

r

=

n

2

R

→n

1

r=n

2

R

i is max when n

1

r=n

2

R

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