Question

D. Sin? 45° + cos² 45° - Tan? 45° QT HTA ETOT
Sin45° + cos 45º – Tan? 45° is equal to​

Answer 1

Explanation:

sin 45 is equal to 1 upon root 2 ....

cos 45 is equal to 1 upon root 2 .....

tan 45 is equal to 1 ..

so sin 45 + cos 45* cos 45 -tan 45=

1/

$1 \div \ \sqrt{2} + 1 \div \sqrt{2} \\ \times 1 \div \sqrt{2} - 1$

=

$1 + \sqrt{2} \div 2 \sqrt{2} - 2 \sqrt{2 } \div 1$