Question

D) The base of a triangle is greater than twice its height by 3 cm. If the
area of the triangle is 44 cm2 , find the base and height of the triangle
​

Answer 1

Answer:

let height of the triangle be x

base= 2x+3

area of triangle =1/2× base×height=44cm*2

then 1/2× 2x+3 ×( x)= 44

2x*2+3x=88

2x*2+3x-88=0

Answer 2

The required equation would be $2x^2+3x-88=0$

Step-by-step explanation:

Since we have given that

Let the height of triangle be 'x'.

Let the base of triangle be '2x+3'

Area of triangle = 44 sq. cm

So, According to question, it becomes,

$\dfrac{1}{2}\times x(2x+3)=44\\\\x(2x+3)=44\times 2\\\\2x^2+3x=88\\\\2x^2+3x-88=0$

Hence, the required equation would be $2x^2+3x-88=0$

# learn more:

D) The base of a triangle is greater than twice its height by 3 cm. If the area of the triangle is 45 cm2 , find the base and height of the triangle​

https://brainly.in/question/15518786