Question

D. The length and breadth of a rectangular garden are in the ratio 7:3. If the area of the field
is 525 m², then find the cost of fencing it at * 75 per m.
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Answer 1

Answer:

Given:-

⟹ The length and breadth of a rectangular

garden are in the ratio 7:3

⟹ the area of the garden is 525 m²

To Find:-

⟹ length and breadth

⟹ and cost of fencing per m

Solution:-

⟹ area = length × breath

⟹ so let the length be 7x and breadth be 3x

⟹7x×3x=525

⟹21x²=525

⟹x²=525÷21

⟹x²=25

⟹x=root 25

⟹x=5

so length:-

⟹7x=7(5)

=35m

breath:-

⟹3(5)

⟹15m

cost of fencing:-

⟹ perimeter ×75

⟹perimeter =2(l+b)

⟹perimeter =2(35+15)

⟹perimeter =2(50)

⟹perimeter =100m

cost=100×75

=7500 rupees

hope this helps.!!

Answer 2

Answer:

• Cost of fencing is 7500.

Step-by-step explanation:

Given :-

• Length and breadth of a rectangular garden are in ratio 7:3.
• Area of rectangular garden is 525 m².

To find :-

• Cost of fencing of garden.

Solution :-

Let, Length of rectangular field be 7x.

And, Breadth of rectangular field be 3x.

• First we will find, Dimensions of rectangular garden for finding fence of garden.

So,

Area of rectangle = Length × Breadth

So,

$\sf \longrightarrow 525 = 7x \times 3x$

$\sf \longrightarrow 525 = 21 x^{2}$

$\sf \longrightarrow \cancel{ \dfrac{525}{21} } = x^{2}$

$\sf \longrightarrow 25 = x^{2}$

$\sf \longrightarrow \sqrt{25} = x$

$\longrightarrow \boxed{\sf x = 5}$

Dimensions :-

• Length = 7x = 7 × 5 = 35 m

• Breadth = 3x = 3 × 5 = 15 m

Perimeter of rectangle = 2(length + breadth)

So,

$\sf \longrightarrow 2 \times (35 + 15)$

$\sf \longrightarrow 70 + 30$

$\sf \longrightarrow \boxed{ \bold{100}}$

Perimeter of garden is 100 m.

• We know, Fence and perimeter are same.

So, Total fence of rectangular garden is 100 m.

• 1 m = 75

For 100 m :-

$\sf \longrightarrow 100 \times 75$

$\sf \longrightarrow \purple{\boxed{\bold{7500}}\star}$

Therefore,

Cost of fencing is 7500.