Question

D The population of a town was 5000, I fit a Increased to 5 500 in one rear, find the percent
increase.​

Answer 1

• population of town = 5000
• increased= 5,500
• 5000 + 5,500 = 10500.
• 10500/5000 * 100
• Hope it helps you! am not sure with the answer!

Answer 2

Given,

The population of a town was $5000$, If it a increased to $5500$ in one year

We have to find the increased percentage

Formula,

Increased% $= \frac{present population - previous population}{previous population}\times100$

Here,

Present population $= 5500$

Previous population $= 5000$

Increased population $=$Present population $-$Previous population

$= 5500-5000=500$

Increased % $=\frac{5500-5000}{5000}\times100$

$= \frac{500}{5000}\times100$

$= 10$%

Therefore, the increased percentage is $10$%.