Question

(d) The sum of four consecutive odd numbers is 80. Find the numbers​

Answer 1

Step-by-step explanation:

17,19,21,23

Let the consecutive odd numbers=x, x+2,x+4, and x+6 respectively.

So,

x+(x+2)+(x+4)+(x+6)=80

4x+(2+4+6)=80

4x+12=80

(4x÷4)+(12÷4)-(12÷4)=(80÷4)-(12÷4)

x+3–3=20–3

x+0=17

x=

17

Given that x=17, then x+2,x+4,and x+6=

19,21, and 23 respectively.

Proof:

17+19+21+23=80

This identity establishes the 4 consecutive odd numbers that = 80

C.H.

Hope its help..

Answer 2

Answer:

Step-by-step explanation:

Given the sum of 4 consecutive odd number is 80

We have to the numbers

Let the first number be 'x', Second number be 'x+2'

Third number be 'x+4' , Fourth  number be 'x+6'

Sum = 80 (given)

⇒ x + x + 2 + x + 4 + x + 6 = 80

⇒ 4x + 12 = 80

⇒ 4x = 68

⇒ x = 17

Hence the first number is 'x' = 17

Second number is 'x+2' = 19

Third number is 'x+4' = 21

Fourth number is 'x+6' = 23