Question

d = ut + 1/2at²
d = 16x10 + 1/2 x 1 x (10x10)

Solve this equation
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Answer 1

Answer:

$d = ut + \frac{1}{2} a {t}^{2} \\ d = 16 \times 10 + \frac{1}{2} \times 1 \times (10 \times 10) \\ d = 160 + \frac{100}{2} \\ d = \frac{(160 \times 2) \: + 100}{2} \\ d = \frac{320 + 100}{2} \\ d = \frac{420}{2} \\ \\ d = 210$

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