d) What is the distance travelled while retarding ?
1 point
40 km
50 km
4oo m
60km
Answers
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0
Answer:
We know that s=
2a
−(v
2
−u
2
)
(negative sign for retarding force.)
Since force is constant, thus acceleration is constant.
In first case with speed u, it stops when v=0, thus s=
2a
−(0−u
2
)
=
2a
u
2
In second case with speed = 2u, s=
2a
−(0−(2u)
2
)
=
2a
4u
2
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