Question

(d){x| x = p+2,p∈ N and p<5} and {13,14,15,16}​

Answer 1

Answer:

{3,4,5,6,7,8} = {x ∈ Z : 3 ≤ x ≤ 8} = {x ∈ N : 3 ≤ x ≤ 8} ... 13. R3 ⊆ R3 is true because any set is a subset of itself. 15. {(x, y) : x−1 ... Plugging d = 2e back into 2a = 7d gives 2a = 14e.