Math, asked by karthik5763, 2 months ago

d³y/dx³+(dy/dx)³-8y=0 find order and degree​

Answers

Answered by mehak5213
1

Answer:

d³y/dx³+(dy/dx)³-8y=0

d^2 y/x^3 + (y/x)^3 -8y=0

on taking L.C.M,

(d^2y +y^3 -8yx^3) / x^3=0

y(d^2 +y^2 -8x^3) = 0

-8x^3 + y^2+ d^2 = 0

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