Question

d5 configuration in high spin state in octahedral complex will have cfse​

Answer 1

d5 configuration in high spin state in octahedral complex will have CFSE 0.

• The formula for calculating CFSE is -0.4$t_{2g}$+0.6$e_{g}$

          [ where $t_{2g}$ is electrons in high energy d orbital (dxy, dyz, dzx) and $e_{g}$ is a low energy d orbital (dx2-y2,dz2)]

• in case of d5 every orbital has one electron.

• So, -0.4$t_{2g}$+0.6$e_{g}$ = -0.4*3+0.6*2 = -1.2+1.2 = 0
• Full form of CFSE is Crystal Field Stabilization energy.