Question

Dad was 7 times older than his son last year,
and this year he is 6 times older than his son.
In how many years will dad be 4 times older
than his son ?​

Answer 1

Answer:

IN 4 YEARS

Step-by-step explanation:

Solution is in the attachment.

Answer 2

After 4 years, dad will be 4 times older

than his son.

Step-by-step explanation:

Let father's present age be f and son's present age be y

Given:

For last year

Relation between father and son age:

f-1 = 7(y-1)

f-1 = 7y-7

f = 7y-6------------(eq1)

For current year

Father's age is 6 times of son's age

f = 6(y)--------(eq 2)

Equating equations 1 and 2:

7y-6 = 6y

so, y = 6 years

The current age of the son is 6 years.

Present age of the father can be found by plugging the value of y in equation 2:

f = 6 x 6= 36 years

Let the father's age be 4 times of son's age after x years, so

f+x = 4(y+x)

36 +x = 4(6 +x)

36 + x= 24 + 4x

12 = 3x

x= 4

Thus, after 4 years, dad will be 4 times older

than his son.

(#SPJ3)