Question

Danae is choosing between two jobs. One job pays an annual bonus of $1,500 plus $120 per day worked. The second job pays an annual bonus of $2,500 plus $110 per day worked. Which equation can be solved to determine after how many days, d, Danae would make the same amount of money regardless of the job she chooses? 120d + 110d = 1,500 + 2,500 120 + 110 = 1,500d + 2,500d 120d + 1,500 = 110d + 2,500 120d + 2,500 = 110d + 1,500

Answer 1

Given:

Two possible jobs for Danae.

Job 1:

Annual bonus = $1,500

Wage for one day = $120

Job 2:

Annual bonus = $2,500

Wage for one day = $110

To find:

Equation to be solved to find the number of days, $d$

such that Danae would make the same amount of money regardless of the job she chooses.

$1) 120d + 110d = 1,500 + 2,500 \\2) 120 + 110 = 1,500d + 2,500d \\3) 120d + 1,500 = 110d + 2,500\\4) 120d + 2,500 = 110d + 1,500$

Solution:

Let us consider the total wages from job 1:

Annual bonus + Money earned by working $d$ number of days

= $1500 + 120 $\times d$

Now, Let us consider the total wages from job 2:

Annual bonus + Money earned by working $d$ number of days

= $2500 + 110 $\times d$

Now, equating both the expressions:

We get the answer as:

$3) 120d + 1,500 = 110d + 2,500$

Solving the equation, we get:

$10d = 1000\\\Rightarrow d =10$

So, after working for 10 days, the money earned by both the jobs will be same.

Answer 2

Answer:

the answer is C bestie

Step-by-step explanation: