Question

Daniel is painting the walls and ceiling of a cuboidal hall with length,breathand height of 15m,10m and 7m respectively. From each can of point 100m2 of area is painted. How many cans of paint will she need to paintthe room​

Answer 1

Answer:

• 5 cans are required to paint the room.

Given:

• Length of wall (l)= 15 m

• Breadth of wall  (b)= 10 m

• Height of wall (h) = 7 m

To find :

• How many cans of paint will she need to paintthe room =?

Step-by-step explanation :

Firstly we find,

Total area to be painted= area of 4 walls + area of ceiling

Lateral surface area of cuboid + Area of Rectangle

= 2(l+b)h + lb

Substituting the values in the above formula, we get

= 2(15+10)7 + 15×10

= 2 × 25 × 7+ 150

= 50× 7+150

= 350+ 150=500

Total area to be painted=500m²

Given, 100m² area can be painted from each can.

Number of cans Required=

Area of hall/ area of 1 can

= 500/100= 5

Hence, 5 cans are required to paint the room.