Question

Daniel is painting the walls and ceiling of a cuboidal hall with length breadth and height of 15m, 10m and 7m respectively from each can of paint 100m of area is painted how many cans of paint will she need to paint the room

Answer 1

I hope this helps you. 5 cans are required that is right answer.

Answer 2

length of cuboidal hall is 15m
breath of cuboidal hall is 10m
and height of cuboidal hall is 7m
so ,Area painted by Daniel of hall,
=area of four walls + area of celling
= 2(l+b)h + l*b
= 2(15 + 10)7 + 15*10
=2*25 * 7 + 150
=350 + 150
=500m square
A to Q,
m square of area is painted by 1 can

then,1 m square of area is painted by 1/100 can

500 m square of area is painted by Daniel in

1/*500= 5can