Question

Daniel is painting the walls and ceiling of a cuboidal Hall of dimensions and 25 m ×12 m × 10 m a from each can obtain 100 cm square of area can be painted how many cans of paint will be needed for the propose

Answer 1

Answer:

Step-by-step explanation:

area of ceiling = l*b = 25*12=300 m², LSA of hall = 25*12*10=3000 m².          total area = 300+3000 = 3300 cm², in one can 100 cm² can be painted . no of cans required = 3300 / 100 = 33 cans. hope it helps