Tha sum to n terms of the series 11 + 103 + 1005 + 10007 + .......to n terms.
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Answer:
Step-by-step explanation:
Sn=n/2[2a+(n-1)d]
Sn=n/2[2×11+(n-1)(92)]
Sn=n/2(22+92n-92)
Sn=n/2(-70+92n)
Sn=n/2×2(46n-35)
Sn=n(46n-35)
Sn=46n²-35n
gargnakul67:
Is the answer correct or not
I don't know.but formula of d=???
d is the subtraction of first term of AP from second
How d= a2-a1 = 92 ???
you are wrong.
try (4a-3a) is not equal to your d=92.
Where is 4a and 3a
if you will try to 10007-1005 isn't equal to 92.
your d=92 is wrong.
kha ka math hai ye
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