Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth, and height of 15m, 10m and 7m respectively. From each can of paint 100m square of area is painted. How many cans of paint will she need to paint the room.

Answer 1

Answer:

DANIEL PAINTING 4 WALLS AND CEILING LENGTH=15M,BERATH=10M,HEIGHT=7M

T.S.A OF CUBOID-L*B

2(LB+BH+HL)_15*10

2(150+70+105)-150

2*325-150

650-150

500M SQUARE

NO. OF CANS=500/100=5CANS

1 Step-by-step explanation:

Answer 2

Surface area of a cuboidal hall without bottom = Total surface area – Area of base

= 2 [lb + bh + hl] – lb

= 2 [15 × 10 + 10 × 7 + 7 × 15] – 15 × 10

= 2[150 + 70 + 105] – 150

= 2 [325] – 150

= 650 – 150

= 500 m2

Area of the paint in one can = 100 m2

Number of cans required = 500100 = 5 cans.