Music, asked by dasmeshsingh983, 3 months ago

dash lies underneath the cuticle. ​

Answers

Answered by madhanarsimhanarsimh
0

Explanation:

{(2x-1) (x - 3) = (x + 5) (x-1)} < /p > < p > < /p > < p > \huge\orange{\overbrace{\red{\underbrace\color{blue}{\underbrace\color{black}{\colorbox{lime}{{\red\:{「Answer」}}}}}}}} < /p > < p > 「Answer」 < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > _______________________________________ < /p > < p > < /p > < p > _______________________________________ < /p > < p > < /p > < p > = > (2x-1) (x - 3) = (x + 5) (x-1)= > (2x−1)(x−3)=(x+5)(x−1) < /p > < p > < /p > < p > = > 2x(x - 3) - 1(x - 3) = x(x - 1) + 5(x - 1)= > 2x(x−3)−1(x−3)=x(x−1)+5(x−1) < /p > < p > < /p > < p > = > 2 {x}^{2} - 6x - x + 3 = {x}^{2} - x + 5x - 5= > 2x < /p > < p > 2 < /p > < p > −6x−x+3=x < /p > < p > 2 < /p > < p > −x+5x−5 < /p > < p > < /p > < p > = > 2 {x}^{2} - {x}^{2} - 6x - x + x - 5x = - 5 - 3= > 2x < /p > < p > 2 < /p > < p > −x < /p > < p > 2 < /p > < p > −6x−x+x−5x=−5−3 < /p > < p > < /p > < p > = > {x}^{2} - 6x - 5x = - 8= > x < /p > < p > 2 < /p > < p > −6x−5x=−8 < /p > < p > < /p > < p > = > {x}^{2} - 11x + 8 = 0= > x < /p > < p > 2 < /p > < p > −11x+8=0 < /p > < p > < /p > < p > Here we use quadratic formula to find out the solution:- < /p > < p > < /p > < p > Here,a=1 ; b=-11 & c=8 < /p > < p > < /p > < p > = > x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a}= > x= < /p > < p > 2a < /p > < p > −b± < /p > < p > b < /p > < p > 2 < /p > < p > −4ac < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > = > x = \frac{ - ( - 11)± \sqrt{ {( - 11)}^{2} - 4(8)} }{2}= > x= < /p > < p > 2 < /p > < p > −(−11)± < /p > < p > (−11) < /p > < p > 2 < /p > < p > −4(8) < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > = > x = \frac{11± \sqrt{121 - 32} }{2}= > x= < /p > < p > 2 < /p > < p > 11± < /p > < p > 121−32 < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > \bold{\red{= > x = \frac{11± \sqrt{89} }{2}}}= > x= < /p > < p > 2 < /p > < p > 11± < /p > < p > 89 < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > < /p > < p > _______________________________________ < /p > < p > < /p > < p > _______________________________________ < /p > < p > < /p > < p > нσρє ıт нєłρs yσυ < /p > < p > < /p > < p > _____________________ < /p > < p > < /p > < p > \: тнαηkyσυ

Answered by MaanieArmyBangtan7
0
Epidermis lies under the cuticle.

Hope it helps ya mate!!!
Pls mark as brainlist!!!!
Thanks sooo much!!! (in advance)
I purple you!!!
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