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find the product of sum of three consecutive
smallest positine numbers with
their corresponding opposites
the
Sum of
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Step-by-step explanation:
Let us assume the numbers to be a, b, c
Therefore their opposites are -a, -b, -c
Now product of the sum of the two
means :
[a+b+c]x[-a+(-b)+(-c)]
=> [a + b + c][-a -b -c]
=> -a^2 -b^2 -c^2 - 2ab - 2bc - 2ac
=> - (a + b + c)^2
Now for smallest values :
a= 1, b =2 and c =3
-(1+2+3)^2 => -(6)^2 => -36
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