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2. In the given figure AD = BC
and BD = Ac
prove that angle adb=angle bca and angle dab=angle cba
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Step-by-step explanation:
In triangles ABD and BAC, we have
AD=BC (given);
AB=AB (common);
AC=BD (given).
We can use SSS condition to conclude that △ABD≅△BAC. From this we conclude that
∠ADB=∠BCA and ∠DAB=∠CBA.
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