Question

Date a . a The e.maf of ocell is balanced by a length of 320 cm of the potentiometer wire. When a cell iš shunted by a resistance of Som the balancing length is reduced by 20 cm. Find interna) on 50 t resistance of the cell.
please answer me.​

Answer 1

Explanation:

Correct option is

B

0.5 Ω

The expression of internal resistance is r=R(

l

2

l

1

−1)=4.5(

45

50

−1)=0.5 Ω

Answer 2

Answer:

The internal resistance of the cell is $50 \Omega .$

Given: The emf of the cell is balanced by a length of 320 cm of the potentiometer wire. When a cell is shunted by the resistance the balancing length is reduced by 20 cm.

To find: The internal resistance of the cell

Calculation:

Data$: R=50 \Omega, l_{1}=320 \mathrm{~cm}, l_{2}=320-20=300 \mathrm{~cm}$

$\begin{aligned}&\mathrm{r}=\mathrm{R}\left(\frac{l_{1}-l_{2}}{l_{2}}\right) \\&=50\left(\frac{320-20}{300}\right) \\&=50 \Omega\end{aligned}$

The internal resistance of the cell is $50 \Omega .$