this is one question with several parts so please solve all the parts
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9. Triangle ABC =180° ( all angles of the triangle equal to 180°)
= A+B+C=180°
= 80+30+C=180
= 110+C. =180
= C= 180-110
C= 70
now angle ACD = angle BAC = 80° ( opposite parrel angle)
angle ACL and ACD are equal so angle ACL= 40°and angle ACD = 40°
Ans= angle ACL = 40°
angle ACD = 40°
Answered by
1
Answer:
Ans= angle ACL = 40°
angle ACD= 40°
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